凱撒密碼簡易解密器

22568

按lz的應(yīng)該這么玩:

1. key=int(input('Input key:'))
   
2. pt=input('Input plaintext:')
   
3. for i in pt:
   
4. if 'a'<=i<='z':
   
5.   print(chr((ord(i)-97+key)%26+97),end='')
   
6. elif 'A'<=i<='Z':
   
7.   print(chr((ord(i)-65+key)%26+65),end='')
   
8. else:
   
9.   print(i,end='')
   
10. print()

復(fù)制代碼