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    發(fā)表于 2026-1-10 00:38:16 福建| 發(fā)自安卓客戶端
    未經(jīng)作者同意,禁止轉(zhuǎn)載本篇謎題
    \boldsymbol{1} = \operatorname{sn}\!\left(\frac{K(k)}{2},k\right)\big/\operatorname{sn}\!\left(\frac{K(k)}{2},k\right)
    boldsymbol{2} = \frac{2\operatorname{sn}(u,k)\operatorname{cn}(u,k)}{\operatorname{sn}(2u,k) \operatorname{sn}(2u,k)=\frac{2\operatorname{sn}(u,k)\operatorname{cn}(u,k)}{\operatorname{dn}(u,k)}, \operatorname{dn}(u,k)=1
    ?\boldsymbol{3} = \frac{3\operatorname{sn}(u,k)\bigl[1-\operatorname{sn}^2(u,k)\bigr]}{\operatorname{sn}(3u,k)
    ?\boldsymbol{4} = \frac{4\operatorname{sn}(u,k)\operatorname{cn}(u,k)\operatorname{dn}(u,k)}{\operatorname{sn}(4u,k)
    ?\boldsymbol{5} = \frac{5\operatorname{sn}(u,k)\bigl[1-10\operatorname{sn}^2
    tran.
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